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chore: Upgrade to Go 1.19 (#3617)

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This is required as part of #3505.
This commit is contained in:
Kyle Carberry
2022-08-21 17:32:53 -05:00
committed by GitHub
parent d37fb054c8
commit b0fe9bcdd1
52 changed files with 144 additions and 86 deletions
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25
coderd/autobuild/schedule/schedule.go
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@ -28,13 +28,14 @@ var defaultParser = cron.NewParser(parserFormat)
// - day of week e.g. 1 (required)
//
// Example Usage:
// local_sched, _ := schedule.Weekly("59 23 *")
// fmt.Println(sched.Next(time.Now().Format(time.RFC3339)))
// // Output: 2022-04-04T23:59:00Z
//
// us_sched, _ := schedule.Weekly("CRON_TZ=US/Central 30 9 1-5")
// fmt.Println(sched.Next(time.Now()).Format(time.RFC3339))
// // Output: 2022-04-04T14:30:00Z
// local_sched, _ := schedule.Weekly("59 23 *")
// fmt.Println(sched.Next(time.Now().Format(time.RFC3339)))
// // Output: 2022-04-04T23:59:00Z
//
// us_sched, _ := schedule.Weekly("CRON_TZ=US/Central 30 9 1-5")
// fmt.Println(sched.Next(time.Now()).Format(time.RFC3339))
// // Output: 2022-04-04T14:30:00Z
func Weekly(raw string) (*Schedule, error) {
if err := validateWeeklySpec(raw); err != nil {
return nil, xerrors.Errorf("validate weekly schedule: %w", err)
@ -115,12 +116,12 @@ var tMax = t0.Add(168 * time.Hour)
// Min returns the minimum duration of the schedule.
// This is calculated as follows:
// - Let t(0) be a given point in time (1970-01-01T01:01:01Z00:00)
// - Let t(max) be 168 hours after t(0).
// - Let t(1) be the next scheduled time after t(0).
// - Let t(n) be the next scheduled time after t(n-1).
// - Then, the minimum duration of s d(min)
// = min( t(n) - t(n-1) ∀ n ∈ N, t(n) < t(max) )
// - Let t(0) be a given point in time (1970-01-01T01:01:01Z00:00)
// - Let t(max) be 168 hours after t(0).
// - Let t(1) be the next scheduled time after t(0).
// - Let t(n) be the next scheduled time after t(n-1).
// - Then, the minimum duration of s d(min)
// = min( t(n) - t(n-1) ∀ n ∈ N, t(n) < t(max) )
func (s Schedule) Min() time.Duration {
durMin := tMax.Sub(t0)
tPrev := s.Next(t0)